Numerical5:DoubleStub(λ/8):Zl:75 + j40Ω,Zo=50Ω
- Short-circuited stubs
- Open-circuited stubs
GIven:
\[
Z_L = 75 + j40\,\Omega
\]
\[
Z_0 = 100\,\Omega
\]
Step 1: Normalized the load impedance by dividing it by characteristic impedance of line. Plot Zn in the Smith Chart. Construct SWR circle for load line recording the wave length at Yn.
\[
z_N = \frac{Z_L}{Z_0}
\]
\[
z_N = \frac{75 + j40}{100}
\]
\[
z_N = \frac{75}{100} + j\frac{40}{100}
\]
\[
z_N = 0.75 + j0.4
\]
SWR = 1.7:1
Yn = 1.0+j0.55
WTGb = 0.349 λ
Step2: Construct λ/8 Circle
The Spacing circle cuts the stub circle at point c and d. Join c and d with the prime circle. Starting at the wavelength reading at the Yn. Move clockwise around the wavelength scale so that the line ends up anywhere between the dashed line C and D. Line C and D describes an arc between two radii that. Point C and D are the points that intersects both SWR and Spacing circle
Draw a straight line from origin to 90 degrees
Draw a bisector line
Draw a circle with bisector line as pivot point
Step 3: Since the distance of 1st stub is not given, we can assume a distance d1 that is d1 distance apart from the load overlapped within the spacing circle or we could assume a point E, and based on WTGE distance can be calculated. For point E, the point should be inside the overlapping region between 1st SWR and spacing Circle.
Overlapping Region:
• The region where the SWR circle and the spacing circle intersect.
• Any point within this overlapping region satisfies both the SWR and the spacing requirements.
Arbitrarily Choosing Point E:
• Within the overlapping region, you can choose any point for the stub placement.
• This point is chosen based on practical considerations or ease of implementation.
For Ease of implementation, Point A (Zn) lies between Spacing Circle and on SWR circle, we chose arbitrarily Point E somewhere between Point A and Point C.
Let us consider a distance to the WTGE as 0.09 λ so that the distance d1 can be calculated. The placement distance of 1st Stub from the load is equal to the clockwise distance from Point B To Point E.
Point E is
\[
y_E = 0.73 + j0.375
\]
\[
D_1 = \text{WTG}_E + \left(0.5\lambda - \text{WTG}_B\right)
\]
\[
D_1 = 0.09\lambda + \left(0.5\lambda - 0.349\lambda\right)
\]
\[
D_1 = 0.09\lambda + 0.151\lambda
\]
\[
D_1 = 0.241\lambda
\]
Step 4: Follow the reactance circle through point E (0.73) in the direction of a smaller reactance. In the case, move left to the point C at the edge of spacing circle and note the coordinates i.e. move anticlockwise towards the edge of the spacing circle. Label the point as F.
Zf = 0.73+j0.04 ohm
Step 5: Find the difference in reactance between point F and E.
\[
\text{The amount of susceptance that must be cancelled is}
\]
\[
X_E - X_F
\]
\[
= j0.375 - j0.04
\]
\[
= j0.335
\]
\[
\therefore \text{Required susceptance to be cancelled} = j0.335
\]
\[
\text{To cancel } +j0.335,\ \text{locate the point } -j0.335
\]
\[
\text{on the susceptance circle and mark it as Point H.}
\]
Also find WTGH
WTGH = 0.448 λ
Step 6: The Stub length is found in the same way as single stub matching. The length of the 1st Stub is calculated as
\[
\text{For the open-circuited stub, measure clockwise from the zero-admittance point.}
\]
\[
L_{1O} = 0.448\lambda
\]
\[
\text{For the short-circuited stub, measure clockwise from the infinite-admittance point.}
\]
\[
L_{1S} = 0.448\lambda - 0.25\lambda
\]
\[
L_{1S} = 0.198\lambda
\]
Step 7: From Point F, again draw 2nd SWR Circle. Using the point F as a circumference location and prime center of the short as a pivot point. Construct a second SWR circle
SWR2 = 1.4:1
Step 8: From point F, move around the 2nd SWR circle in clockwise direction until reaching to R=1 circle on the inside of the spacing circle, note the edge as G.
ZG = 1+j0.35
Step 9: Find the point -j0.35to cancel j0.35 and note it as Point I
Now draw a line to that point
WTGI = 0.446 λ
Step 9: The Stub length is found in the same way as single stub matching. The length of the 2nd Stub is calculated as
\[
\text{For the open-circuited stub, measure clockwise from the zero-admittance point.}
\]
\[
L_{2O} = 0.446\lambda
\]
\[
\text{For the short-circuited stub, measure clockwise from the infinite-admittance point.}
\]
\[
L_{2S} = 0.446\lambda - 0.25\lambda
\]
\[
L_{2S} = 0.196\lambda
\]