Numerical 2

What are the Characteristics of Chebyshev filter? Derive an expression to calculate the order of given low pass specification using Chebyshev approximations and calculate the order of the given specifications.

Passband extending from w = 0 rad/s to w=1000 rad/s, the attenuation shouldn’t exceed 0.25db

Stopband extending from w = 2500rad/s to w = infinity, the attenuation shouldn’t be less than 40db.

From Question:

$
\begin{aligned}
\textbf{Given:} \quad 
\omega_p &= 1000 \, \text{rad/s}, \quad 
\omega_s = 2500 \, \text{rad/s} \\
\alpha_{\text{max}} &= 0.25 \, \text{dB}, \quad 
\alpha_{\text{min}} = 40 \, \text{dB}
\end{aligned}
$

Here,

$
n = \frac{ \cosh^{-1} \left( \sqrt{ \frac{10^{\frac{40}{10}} - 1}{10^{\frac{0.25}{10}} - 1} } \right) }
{ \cosh^{-1} \left( \frac{\omega_s}{\omega_p} \right) }
= \frac{ \cosh^{-1} \left( \sqrt{ \frac{10000 - 1}{1.059 - 1} } \right) }
{ \cosh^{-1} (2.5) }
\approx \frac{ \cosh^{-1}(464.2) }{ \cosh^{-1}(2.5) }
\approx \frac{6.14}{1.448} \approx 4.238 \Rightarrow n \approx 5
$

The Ripple Factor is given by:

$
\varepsilon = \sqrt{10^{\frac{0.25}{10}} - 1} = \sqrt{1.059 - 1} = \sqrt{0.059} \approx 0.2434
$

$
v = \pm \frac{1}{n} \sinh^{-1}\left( \frac{1}{\varepsilon} \right)
= \pm \frac{1}{5} \sinh^{-1}(4.108) 
\approx \pm \frac{1}{5} \cdot 2.1206 \approx \pm 0.4241
$

Angle Components \( u_k \):

$
u_k = \frac{(2k+1)\pi}{2n}, \quad \text{for } k = 0,1,\dots,9
$

$
\begin{aligned}
u_0 &= \frac{\pi}{10}, \quad u_1 = \frac{3\pi}{10}, \quad u_2 = \frac{5\pi}{10}, \\
u_3 &= \frac{7\pi}{10}, \quad u_4 = \frac{9\pi}{10}, \quad u_5 = \frac{11\pi}{10}, \\
u_6 &= \frac{13\pi}{10}, \quad u_7 = \frac{15\pi}{10}, \quad u_8 = \frac{17\pi}{10}, \quad u_9 = \frac{19\pi}{10}
\end{aligned}
$

The Poles locations are given by:

$
\begin{aligned}
S_0 &= \phantom{-}0.135 + j\,1.0375 \\
S_1 &= \phantom{-}0.353 + j\,0.6414 \\
S_2 &= \phantom{-}0.4369 \\
S_3 &= \phantom{-}0.353 - j\,0.6414 \\
S_4 &= \phantom{-}0.135 - j\,1.0375 \\
S_5 &= -0.135 - j\,1.0375 \\
S_6 &= -0.353 - j\,0.6414 \\
S_7 &= -0.4369 \\
S_8 &= -0.353 + j\,0.6414 \\
S_9 &= -0.135 + j\,0.378
\end{aligned}
$

Selected Poles (Left Half s-Plane):

$
S_5 = -0.135 - j\,1.0375, \quad 
S_6 = -0.353 - j\,0.6414, \quad 
S_7 = -0.4369, \quad 
S_8 = -0.353 + j\,0.6414, \quad 
S_9 = -0.135 + j\,0.378
$

We only take values on the negative half of the s-plane, the poles are S5, S6, S7, S8, S9

The Transfer Functions

$
\begin{aligned}
T(s) &= \frac{1}
{(s - S_5)(s - S_6)(s - S_7)(s - S_8)(s - S_9)} \\
&= \frac{1}
{(s + 0.135 + j\,1.037)(s + 0.353 + j\,0.6414)(s + 0.4369)(s + 0.353 - j\,0.6414)(s + 0.135 - j\,0.378)}
\end{aligned}
$

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